The mass percent of citric acid in the candy sample is 5.83%.
The chemical equation for the reaction is:
C₂H₂O(CO₂H)₃ (aq) + 3OH⁻ (aq) → C₂H₂O(CO₂)₃ (aq) + 3H₂O (l)
This is a neutralization reaction, which is a type of acid-base reaction. The citric acid is the acid in the reaction, and the sodium hydroxide is the base. The products of the reaction are a salt (citrate salt) and water.
To calculate the mass percent of citric acid in the sample, we can use the following equation:
mass percent citric acid = (mass of citric acid / mass of sample) * 100%
We know that the mass of the sample is 16.00 g. The mass of citric acid can be calculated using the following equation:
We know that the volume of NaOH solution is 14.2 mL and the molarity of NaOH solution is 0.340 M. Substituting these values into the equation, we get:
moles of citric acid = 14.2 mL * 0.340 M = 4.87 mmol
The molar mass of citric acid is 192.12 g/mol. Substituting this value into the equation for mass of citric acid, we get:
mass of citric acid = 4.87 mmol * 192.12 g/mol = 0.932 g
Now we can calculate the mass percent of citric acid in the sample:
mass percent citric acid = (0.932 g / 16.00 g) * 100% = 5.83%