Final answer:
The distribution of the total weight of the 5 randomly selected apples is approximately normal with a mean of 45 ounces and a standard deviation of 1.32 ounces. The probability that the total weight will be less than 42 ounces is approximately 1.18%. The mean and standard deviation of the complete packaged gift box, including the packing material and box, are 55 ounces and 1.32 ounces, respectively.
Step-by-step explanation:
The distribution of the total weight of the 5 randomly selected apples can be described as approximately normally distributed, with a mean equal to the sum of the mean weights of the individual apples (5 times the mean weight of a single apple) and a standard deviation equal to the square root of the sum of the variances of the individual apples.
In this case, the mean of the total weight would be 5 times 9 ounces, which is 45 ounces, and the standard deviation would be the square root of 5 times 0.75 squared, which is approximately 1.32 ounces.
To find the probability that the total weight of the 5 randomly selected apples will be less than 42 ounces, we can use the z-score formula.
The z-score is calculated by subtracting the mean from the desired value (42 ounces) and then dividing by the standard deviation.
With a z-score of -2.27, we can use a standard normal distribution table or calculator to find the corresponding probability, which is approximately 0.0118 or 1.18%.
To find the mean and standard deviation of the complete packaged gift box, we need to add the weight of the packing material and box (10 ounces) to the total weight of the 5 randomly selected apples.
This gives us a mean of 45 + 10 = 55 ounces and a standard deviation of 1.32 ounces.