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a pulse is sent down a transmission line that is not functioning properly. it has a propagation velocity of 2.1 x 108 m/s, and an inverted reflected pulse (equal in magnitude to the incident pulse) is returned in .731 ms. what is wrong with the line, and how far from the generator does the fault exit?(10 points

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Final answer:

The inverted reflected pulse suggests a short or an open circuit in the transmission line. The distance from the generator to the fault is determined using the formula Distance = (Propagation Velocity x Time of Flight) / 2.

Step-by-step explanation:

The inverted reflected pulse returning in a faulty transmission line suggests that there is a short or an open circuit in the line. When a pulse reaches the end of the line, it reflects back towards the source. In a properly functioning transmission line, the reflected pulse should have the same magnitude and direction as the incident pulse. However, in this case, the reflected pulse is inverted, indicating a mismatch in impedance between the transmission line and the load.

To find the distance from the generator to the fault, we can use the formula:

Distance = (Propagation Velocity x Time of Flight) / 2

Plugging in the given values:

Distance = (2.1 x 10^8 m/s) x (0.731 x 10^-3 s) / 2 = 76,791.45 m

User John Paul Manoza
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