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when wine is not properly stored, it can undergo oxidative fermentation, where ethanol reacts with oxygen to produce acetic acid and water , according to the given balanced equation. how many grams of water are formed from of ethanol ? round your answer to significant figures.

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The 42.036 grams of acetic acid are formed from 0.70 mol of ethanol.

The balanced chemical equation for the reaction is:

C₂H₆O(aq) + O₂(g) → C₂H₄O₂(aq) + H₂O(l)

To solve this question, we can use the following steps:

Calculate the molar mass of acetic acid:

M(C₂H₄O₂) = 2C + 4H + 2O = 2 × 12.011 g/mol + 4 × 1.008 g/mol + 2 × 15.999 g/mol = 60.052 g/mol

Use the stoichiometry of the balanced chemical equation to calculate the moles of acetic acid produced:

1 mol C₂H₆O produces 1 mol C₂H₄O₂

Therefore, 0.70 mol C₂H₆O produces 0.70 mol C₂H₄O₂

Calculate the mass of acetic acid produced:

mass of acetic acid = moles of acetic acid × molar mass of acetic acid

mass of acetic acid = 0.70 mol C₂H₄O₂ × 60.052 g/mol

C₂H₄O₂ = 42.036 g.

when wine is not properly stored, it can undergo oxidative fermentation, where ethanol-example-1
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