The 42.036 grams of acetic acid are formed from 0.70 mol of ethanol.
The balanced chemical equation for the reaction is:
C₂H₆O(aq) + O₂(g) → C₂H₄O₂(aq) + H₂O(l)
To solve this question, we can use the following steps:
Calculate the molar mass of acetic acid:
M(C₂H₄O₂) = 2C + 4H + 2O = 2 × 12.011 g/mol + 4 × 1.008 g/mol + 2 × 15.999 g/mol = 60.052 g/mol
Use the stoichiometry of the balanced chemical equation to calculate the moles of acetic acid produced:
1 mol C₂H₆O produces 1 mol C₂H₄O₂
Therefore, 0.70 mol C₂H₆O produces 0.70 mol C₂H₄O₂
Calculate the mass of acetic acid produced:
mass of acetic acid = moles of acetic acid × molar mass of acetic acid
mass of acetic acid = 0.70 mol C₂H₄O₂ × 60.052 g/mol
C₂H₄O₂ = 42.036 g.