Question

consider a cylinder initially filled with 8.79 10-4 m3 of ideal gas at atmospheric pressure. an external force is applied to slowly compress the gas at constant temperature to 1/2 of its initial volume. calculate the work that is done. note that atmospheric pressure is 1.013 105 pa.

Answer 1

The work done is -4.46 J.

Step-by-step explanation:

To calculate the work done, we use the formula:

Work = -PΔV

Where P is the pressure and ΔV is the change in volume.

In this case, the initial volume is V1 = 8.79 x 10^-4 m3 and the final volume is V2 = 1/2 x 8.79 x 10^-4 m3.

The atmospheric pressure is given as 1.013 x 10^5 Pa.

Plugging these values into the formula, we get:

Work = -P(V2 - V1)

Work = -1.013 x 10^5 Pa x (1/2 x 8.79 x 10^-4 m3 - 8.79 x 10^-4 m3)

Work = -1.013 x 10^5 Pa x 8.79 x 10^-4 m3/2

Work = -4.46 J