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64 - 48bottle a contains more soda than bottle b. pour from bottle a into bottle b as much soda as b already contains. now pour from b into a as much soda as a now contains. then pour from a into b as much soda as b now contains. each bottle now contains 64 ounces. how many more ounces of soda were in bottle a than bottle b at the beginning?

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Final answer:

The question asks how many more ounces of soda were in bottle A than bottle B at the beginning. Through a step-by-step analysis, it is determined that there was no difference in the amount of soda between bottle A and bottle B at the beginning.

Step-by-step explanation:

To determine how many more ounces of soda were in bottle A than bottle B at the beginning, we need to analyze the information given in the question. First, let's assign variables: let a represent the amount of soda in bottle A and b represent the amount of soda in bottle B.

According to the question, after pouring from bottle A to bottle B, both bottles contain 64 ounces of soda. This means that a - b = 64. After pouring from bottle B to bottle A, both bottles still contain 64 ounces of soda. This means that a - b = 64.

Since both equations have the same value, we can equate them and solve for a:

a - b = 64 and a - b = 64. Subtracting the second equation from the first equation, we get:

0 = 0.

This shows that there was no difference in the amount of soda between bottle A and bottle B at the beginning. Therefore, there were 0 more ounces of soda in bottle A than bottle B.

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