Question

in 1939, joe sprinz of the san francisco seals baseballclub attempted to catch a ball dropped from a blimp at aheight of 800 ft (for the purpose of breaking the record forcatching a ball dropped from the greatest height set the pre-ceding year by members of the cleveland indians).(a) how long does it take for a ball to drop 800 ft?(b) what is the velocity of a ball in miles per hour after an800 ft drop (88 ft/s

Answer 1

To calculate the time it takes for a ball to drop 800 ft, we can use the equation t = sqrt(2h/g), where h is the height and g is the acceleration due to gravity. The time comes out to be approximately 7.07 seconds. The velocity of the ball after an 800 ft drop is approximately 154.09 mph.

Step-by-step explanation:

To answer the first part of the question, we can calculate the time it takes for a ball to drop 800 ft using the equation t = sqrt(2h/g), where h is the height and g is the acceleration due to gravity. Plugging in the values, we get t = sqrt(2 * 800/32) = sqrt(50) ∼ 7.07 seconds.

In the second part, to calculate the velocity of the ball after an 800 ft drop, we can use the formula v = gt, where g is the acceleration due to gravity and t is the time it takes to drop.

Substituting the values, we have v = 32 * 7.07 = 225.44 ft/s. To convert this to miles per hour,

we can multiply by 3600/5280 (the number of feet in a mile and the number of seconds in an hour),

we get v = 225.44 * 3600/5280

= 154.09 mph.