Final answer:
To find the function f given the second derivative f''(x) = 12x + 36x^2, integrate the equation twice to get f(x) = 2x^3 + 3x^4 + Cx + D.
Step-by-step explanation:
To find the function f given the second derivative f''(x) = 12x + 36x^2, we need to integrate the given equation twice. Let's start with the first integration:
∫ f''(x) dx = ∫ (12x + 36x^2) dx
By integrating, we get:
f'(x) = 6x^2 + 12x^3 + C
Next, we integrate again:
∫ f'(x) dx = ∫ (6x^2 + 12x^3 + C) dx
After integration, we have:
f(x) = 2x^3 + 3x^4 + Cx + D
Therefore, the function f is given by f(x) = 2x^3 + 3x^4 + Cx + D, where C and D are constants.