Question

determine the volume of nitrogen gas (in liters, at 317. k and 1.00 atm) required to react with 8.00 l of 0, gas at 375. k and 1.20 atm. round your answer to 3 significant figures.

Answer 1

The volume of nitrogen gas required to react with 8.00 L of gas at different conditions is 2.032 L.

Step-by-step explanation:

To determine the volume of nitrogen gas required to react with 8.00 L of gas, we need to use the ideal gas law equation:

P1V1/T1 = P2V2/T2

Given:

P1 = 1.20 atm

V1 = 8.00 L

T1 = 375 K

P2 = 1.00 atm

T2 = 317 K

Solving for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Substituting the given values:

V2 = (1.20 atm * 8.00 L * 317 K) / (1.00 atm * 375 K)

= 2.032 L

Therefore, the volume of nitrogen gas required is approximately 2.032 L.