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you decide to invest $6,000 at a 6% interest rate, compounded monthly. how long will it take you to have a balance of $24,000 in your account? round your answer to the nearest whole number.

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Final answer:

Using the compound interest formula, it would take approximately 23 years for a $6,000 investment to grow to $24,000 with a 6% annual interest rate compounded monthly.

Step-by-step explanation:

To determine how long it will take to grow an initial investment of $6,000 to $24,000 at a 6% interest rate, compounded monthly, we can use the formula for compound interest:

A = P (1 + \frac{r}{n})^{nt}

Where:

  • A is the amount of money accumulated after n years, including interest.
  • P is the principal amount (the initial amount of money).
  • r is the annual interest rate (decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested for, in years.

First, we need to solve for t when A is $24,000, P is $6,000, r is 0.06 (since 6% is 0.06 as a decimal), and n is 12 (since the interest is compounded monthly).

Putting these values into the formula:

$24,000 = $6,000 (1 + \frac{0.06}{12})^{12t}

Now we solve for t. We first divide both sides by $6,000:

4 = (1 + \frac{0.06}{12})^{12t}

We then take the natural logarithm of both sides:

ln(4) = ln((1 + \frac{0.06}{12})^{12t})

ln(4) = 12t * ln(1 + \frac{0.06}{12})

Then, we divide both sides by (12 * ln(1 + 0.06/12)) to solve for t:

t = \frac{ln(4)}{12 * ln(1 + \frac{0.06}{12})}

Using a calculator, we find that t is approximately 23.45 years, which can be rounded to the nearest whole number as 23 years.

It will take approximately 23 years for the $6,000 investment to grow to $24,000 with a 6% interest rate, compounded monthly.

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