Question

an object's moment of inertia is 2.50 kgm2 . its angular velocity is increasing at the rate of 4.00 rad/s2 . part a what is the net torque on the object?

Answer 1

The net torque on an object with a moment of inertia of 2.50 kg·m2 and an angular acceleration of 4.00 rad/s2 is 10.0 N·m.

Step-by-step explanation:

The student has posed a physics question regarding the net torque on an object, given its moment of inertia and angular acceleration.

To find the net torque, we use the fundamental physics relationship τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

Substituting the values provided by the student, we have a moment of inertia (I) of 2.50 kg·m2 and an angular acceleration (α) of 4.00 rad/s2.

Therefore, the net torque (τ) can be calculated as:

τ = (2.50 kg·m2)(4.00 rad/s2)

τ = 10.0 N·m

Thus, the net torque on the object is 10.0 Newton-meters (N·m).