Final answer:
The mass of sodium fluoride formed from the reaction of 11.5 g of fluorine with enough sodium can be calculated using the molar ratio and molar mass.
Step-by-step explanation:
To determine the mass of sodium fluoride formed from the complete reaction of 11.5 g of fluorine, we need to calculate the molar ratio between sodium and fluorine in the reaction.
The balanced equation is:
2 Na + F2 → 2 NaF
From the balanced equation, we can see that 2 moles of sodium react with 1 mole of fluorine to form 2 moles of sodium fluoride.
To find the molar mass of sodium fluoride, we add the atomic masses of sodium (22.99 g/mol) and fluorine (18.998 g/mol), which gives us a molar mass of 41.99 g/mol.
Using the molar ratio and molar mass, we can calculate:
(11.5 g F2) × (1 mol NaF / 1 mol F2) × (41.99 g NaF / 1 mol NaF)
= 243.42 g NaF
Therefore, the mass of sodium fluoride formed from the complete reaction is 243.42 grams.