Question

a 5 kg block is pulled up at a constant speed on a frictionless incline angled at 20 degrees above the horizontal. what force is the block pulled with? (round to the nearest tenth). n

Answer 1

The 5 kg block is pulled up the incline with a force of 16.7 N.

Step-by-step explanation:

To find the force with which the 5 kg block is pulled up the frictionless incline, we need to determine the component of the force acting parallel to the incline.

This can be found using the formula F = mg sin(theta), where F is the force, m is the mass of the block, g is the acceleration due to gravity, and theta is the angle of the incline.

Plugging in the values, we have

F = (5 kg)(9.8 m/s^2) sin(20 degrees)

= 16.7 N.

Therefore, the block is pulled up with a force of 16.7 N.