Question

in a titration, a 25.00 ml sample of sodium hydroxide solution was neutralizaed by 32.72 ml of hydrochloric acid. the molarity of the acid is .192 m. find the concentration of the basic solution

Answer 1

To find the concentration of the NaOH solution, we can use the formula: M1V1 = M2V2. Plugging in the values, we get M2 = (0.192 M)(32.72 mL) / (25.00 mL) = 0.252 M. Therefore, the concentration of the NaOH solution is 0.252 M.

Step-by-step explanation:

In this titration, sodium hydroxide (NaOH) solution is being neutralized by hydrochloric acid (HCl).

The volume of NaOH used is 32.72 mL and the molarity of HCl is 0.192 M.

To find the concentration of the NaOH solution, we can use the formula:

M1V1 = M2V2

Where M1 is the molarity of HCl, V1 is the volume of HCl used, M2 is the molarity of NaOH, and V2 is the volume of NaOH used.

Plugging in the values:

(0.192 M)(32.72 mL) = (M2)(25.00 mL)

Solving for M2, the concentration of the NaOH solution, we get:

M2 = (0.192 M)(32.72 mL) / (25.00 mL)

M2 = 0.252 M

Therefore, the concentration of the NaOH solution is 0.252 M.