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a neutron star of mass 3.5 x 1030 kg and radius 5 km rotates. what is its moment of inertia (leave as x 1036)

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Final answer:

The moment of inertia of the neutron star is 7 x 10^30 kg m^2.

Step-by-step explanation:

The moment of inertia of a rotating object can be calculated using the formula:

I = (2/5) * m * r^2

where I is the moment of inertia, m is the mass, and r is the radius of the object.

In this case, the mass of the neutron star is given as 3.5 x 10^30 kg and the radius as 5 km (or 5 x 10^3 m).

Substituting these values into the formula, we have:
I = (2/5) * (3.5 x 10^30 kg) * (5 x 10^3 m)^2

Which simplifies to:
I = 7 x 10^30 kg m^2

User Felipe Santana
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