Final answer:
To prepare 1.50 L of a 5.00 M NaOH solution, 300.00 grams of NaOH are required, which is calculated using the molarity formula and the molar mass of NaOH (40.00 g/mol).
Step-by-step explanation:
Calculating Grams of Solute for NaOH Solution
To calculate the grams of solute needed to prepare a 1.50 L of a 5.00 M NaOH solution, we use the formula:
molarity (M) = moles of solute (n) / volume of solution in liters (V)
First, we rearrange the formula to solve for moles of solute (n):
n = molarity (M) × volume of solution in liters (V)
Substitute the given values:
n = 5.00 M × 1.50 L = 7.5 moles
Now we convert the moles of NaOH to grams using its molar mass:
molar mass of NaOH = 40.00 g/mol
grams of NaOH = moles × molar mass
grams of NaOH = 7.5 moles × 40.00 g/mol = 300.00 grams
Therefore, to prepare 1.50 L of a 5.00 M NaOH solution, 300.00 grams of NaOH are needed.