Question

Determine the specified confidence interval.

It has been estimated, with 90% confidence, the proportion of Americans who go out shopping on Black Friday is 0.40 with a margin of error equal to 0.04.
Determine the resulting 90% confidence interval for the proportion of Americans who go out shopping on Black Friday.

Answer 1

To determine the 90% confidence interval for the proportion of Americans who go out shopping on Black Friday, subtract the margin of error from the estimated proportion to find the lower bound and add the margin of error to the estimated proportion to find the upper bound.

Step-by-step explanation:

To determine the 90% confidence interval for the proportion of Americans who go out shopping on Black Friday, we can use the margin of error and the estimated proportion of the population. The margin of error is equal to 0.04, which means that the estimate could be off by 0.04. The estimated proportion is 0.40. To calculate the confidence interval, we subtract the margin of error from the estimated proportion to find the lower bound and add the margin of error to the estimated proportion to find the upper bound.

The lower bound is 0.40 - 0.04 = 0.36 and the upper bound is 0.40 + 0.04 = 0.44. Therefore, the resulting 90% confidence interval for the proportion of Americans who go out shopping on Black Friday is (0.36, 0.44).