Question

Triangle VWX with vertices V(-1, 0). W(6, 8), C(5, 6), and D(2, 1): (x, y) → (x + 2, y - 6) and X（4.-3）：（x,y） → （x-1.9-5）

Answer 1

After Triangle VWX goes through a translation with a rule of (x, y) + (x-1, y-5) the coordinated of the triangle would be V' (-2,-5) , W' (5,3) and X' (3,-8)

We want to find the coordinates of triangle VWX with vertices of V(-1,0), W(6,8), and X(4, -3) after a translation following the rule (x, y) + (x-1, y-5)

To do this we simply follow the rule and apply it to the given vertices of triangle VWX

Explanation of rule:

(x, y) + (x-1, y-5)

subtract 1 from the x values and subtract 5 from the y values of the given coordinates before the translation

Translation rule being applied:

V (-1,0) -----> ( -1 - 1 = -2 , 0 - 5 = -5 ) -----> (-2,-5)

W (6,8) -----> ( 6 - 1 = 5 , 8 - 5 = 3 ) -----> (5,3)

X (4,-3) -----> ( 4 - 1 = 3 , - 3 - 5 = -8 ) -----> (3,-8)

So after Triangle VWX goes through a translation with a rule of (x, y) + (x-1, y-5) the coordinated of the triangle would be V' (-2,-5) , W' (5,3) and X' (3,-8)

Complete question:

Triangle VWX with vertices V(-1, 0). W(6, 8), X(4.-3), and (x,y) - (x-1, y-5）