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In a right triangle, the measures of the legs are x and x + 14 and the measure of the hypotenuse is x + 16. Find the measure of x.

User Likk
by
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1 Answer

8 votes

Answer:


x=10

Explanation:

We can use the Pythagorean Theorem:


a^2+b^2=c^2

The two legs are x and (x + 14) and the hypotenuse is (x + 16). Therefore:


(x)^2+(x+14)^2=(x+16)^2

Expand:


\displaystyle x^2+(x^2+28x+196)=x^2+32x+256

Combine like terms:


2x^2+28x+196=x^2+32x+256

Subtract the right from the left:


(2x^2+28x+196)-(x^2+32x+256)=0

Subtract:


x^2-4x-60=0

Factor:


(x-10)(x+4)=0

Zero Product Property:


x-10=0\text{ or } x+4=0

Solve:


\displaystyle x = 10 \text{ or } x = -4

The x cannot be negative since a side cannot measure -4. So, our only answer is:


x=10

So, the legs are 10 and 24 with the hypotenuse being 26.

User HyeEun
by
8.1k points

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