Answer:

Explanation:
We want the equation of a line with a slope of 10 and passes through (-4, -25).
We can use the point-slope form given by:

Where m is the slope and (x₁, y₁) is a point.
So, we will substitute 10 for m and (-4, -25) for (x₁, y₁):

Simplify:

Distribute:

Subtract 25 from both sides:

And we have our equation.