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Graph the line that has a slope of 1 /3 and includes the point (0,8).

User Jeatsy
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The graph of the line with a slope of 1/3 and passing through the point (0,8) is a straight line that passes through the point (0,8) and has a slope of 1/3.

To graph the line with a slope of 1/3 and passing through the point (0,8), we can use the point-slope form of the equation of a line:

[ y - y_1 = m(x - x_1) ]

where m is the slope, and (x1, y1) is the given point.

Substituting the given values, we get:

[ y - 8 = \frac{1}{3}(x - 0) ]

Simplifying the equation, we get:

[ y - 8 = \frac{1}{3}x ]

[ y = \frac{1}{3}x + 8 ]

Therefore, the equation of the line is y = (1/3)x + 8. To graph the line, we can plot the given point (0,8) and then use the slope to find another point on the line. Since the slope is 1/3, we can go up 1 unit and to the right 3 units from the point (0,8) to get another point on the line. Plotting these two points and connecting them with a straight line, we get:

Graph of line with slope 1/3 passing through point (0,8)

Therefore, the graph of the line with a slope of 1/3 and passing through the point (0,8) is a straight line that passes through the point (0,8) and has a slope of 1/3.

Graph the line that has a slope of 1 /3 and includes the point (0,8).-example-1
User Jemlifathi
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