Question

Which of these steps follows the most logical order for a low-to-high sorting algorithm?

A: Scan to find the smallest number
Set to 0 in the index in the output array
Remove that number from the input array
Repeat steps 1-3, but add 1 to the index number for each loop
B: Scan to find the smallest number
Set the length of the array in the index in the output array
Remove that number from the input
Repeat steps 1-3, but add 1 to the index number for each loop
C: Scan to find the smallest number
Set to 0 in the index in the output array
Remove that number from the input array
D: Scan to find the largest number
Set to 0 in the index in the output array
Remove that number from the input array
Repeat steps 1-3, but add 1 to the index number for each loop

Answer 1

The most logical steps for a low-to-high sorting algorithm is to repeatedly find the smallest number, place it at the current index in the output array, and then remove it from the input array before moving to the next index.

Step-by-step explanation:

The most logical order for a low-to-high sorting algorithm is described in option A. This method involves repeating a series of steps to organize an array:

1. Scan to find the smallest number in the input array.
2. Set to 0 in the index in the output array for the first found smallest number.
3. Remove that number from the input array.
4. Repeat steps 1-3, but add 1 to the index number for each loop to place the next smallest number in the subsequent position in the output array.

This approach is also known as selection sort, where the smallest number is continuously selected and placed at the current index, which increments with each iteration.