Question

What is the MIPS assembly code for the C statement: a = b * c + a;?

a) mul $t0, $s1, $s2; add $s0, $t0, $s0;
b) add $t0, $s1, $s2; mul $s0, $t0, $s0;
c) add $s0, $t0, $s0; mul $t0, $s1, $s2;
d) mul $s0, $t0, $s0; add $t0, $s1, $s2;

Answer 1

The MIPS assembly code for the C statement a = b * c + a; is option a) mul $t0, $s1, $s2; add $s0, $t0, $s0; which performs a multiplication of b and c, and then adds the result to a.

Step-by-step explanation:

The MIPS assembly code for the C statement a = b * c + a; would require both multiplication and addition operations. In MIPS assembly, the multiplication is done using the mul instruction, and addition is done using the add instruction. Assuming that a, b, and c are stored in registers $s0, $s1, and $s2 respectively, the following MIPS code performs the required operation:

mul $t0, $s1, $s2;
add $s0, $t0, $s0;

Therefore, the correct answer is a) mul $t0, $s1, $s2; add $s0, $t0, $s0;. First, $s1 and $s2 are multiplied, with the result being stored in temporary register $t0. Then, the content of $s0 (which holds the value of a) is added to the result of the multiplication stored in $t0, with the final result being stored back in $s0.