Final answer:
The number of moles of ethanol needed to produce 0.10 mol of acetic acid is 0.10 mol.
Step-by-step explanation:
To calculate the moles of ethanol needed to produce 0.10 mol of acetic acid, we need to use the balanced chemical equation and stoichiometry. The balanced equation for this reaction is:
C2H5OH + O2 → CH3COOH + H2O
From the equation, we can see that the mole ratio between ethanol and acetic acid is 1:1. Therefore, the number of moles of ethanol needed to produce 0.10 mol of acetic acid is also 0.10 mol.