63.0k views
0 votes
Which of the following shows the true solution to the logarithmic equation below? log(x)+log(x+5)=log(6x+12)

a. x=−8
b. y=4
c. x=−3 and x=4
d. x=−3 and x=−4

1 Answer

5 votes

Final answer:

To solve the logarithmic equation, combine the logarithms on the left side of the equation using the property log(a) + log(b) = log(ab). Simplify the resulting equation and find the solutions using factoring or the quadratic formula. The true solution to the logarithmic equation is x = -3 and x = 4.

Step-by-step explanation:

To solve the logarithmic equation, you can combine the logarithms on the left side of the equation using the property log(a) + log(b) = log(ab).

Applying this property, the equation becomes log(x*(x+5)) = log(6x+12).

Since the logarithms are equal, the quantities inside the logarithms must also be equal, so x*(x+5) = 6x+12.

Expanding and rearranging the equation, we get
x^2 + 5x - 6x - 12 = 0.

Simplifying further, we have
x^2 - x - 12 = 0

Factoring or using the quadratic formula, we find the solutions to be x = -3 and x = 4.

Therefore, the true solution to the logarithmic equation is x = -3 and x = 4.

User Altiano Gerung
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories