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When one mole of C6H6 is burned, 3.27 MJ of heat is produced. If the heat from burning 8.29 g of C6H6 is added to 5.69 kg of water at 21.0 degrees Celsius, what is the final temperature of the water?

User Oimitro
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Final answer:

First, calculate the heat released by burning 8.29 g of C6H6 using the heat of combustion information. Then, determine the temperature change of water by dividing the heat released by the product of the mass of water and the specific heat capacity. Finally, add this temperature change to the initial temperature to get the final temperature.

Step-by-step explanation:

To determine the final temperature of water after burning benzene (C6H6), first, we should calculate the total amount of heat released by burning 8.29 g of C6H6. Since 1 mole (78.11 g) of C6H6 releases 3.27 MJ of heat, we can set up a proportion to find the heat released from 8.29 g.

Heat released = (8.29 g / 78.11 g) × 3.27 MJ

Next, we convert this energy to joules and use the specific heat capacity of water (4.184 J/g°C) to calculate the temperature change. The mass of the water is 5.69 kg, which is 5690 g.

ΔT = Heat released / (mass of water × specific heat capacity of water)

Finally, add the temperature change to the initial temperature of the water to find the final temperature.

Final Temperature = Initial Temperature + ΔT

User Alexis Tyler
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