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What temperature (in °C) did an ideal gas shift to if it was initially at -26.0 °C at 4.62 atm and 35.0 L, and the pressure was changed to 8.51 atm, and the volume changed to 20.0 L?

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Final answer:

By applying the combined gas law and converting the temperatures to Kelvin, we can calculate the final temperature of the gas after the pressure and volume changes. Initial values are converted to Kelvin, the combined gas law formula is applied, and then the final temperature is converted back to Celsius.

Step-by-step explanation:

The question pertains to an ideal gas law problem. We can use the combined gas law, which relates the pressure, volume, and temperature of an ideal gas, to find the final temperature of the gas after changes in pressure and volume. The combined gas law formula is given as (P1 * V1) / T1 = (P2 * V2) / T2, where P stands for pressure, V for volume, and T for temperature in Kelvins. We need to convert the initial temperature from Celsius to Kelvin before performing our calculations. The Kelvin and Celsius scales are related by the formula T(K) = T(°C) + 273.15.

The initial pressure (P1) is 4.62 atm, the initial volume (V1) is 35.0 L, and the initial temperature (T1) is -26.0 °C, which is 247.15 K. The final pressure (P2) is 8.51 atm, and the final volume (V2) is 20.0 L. Applying the formula, we find the final temperature (T2) in Kelvins and then convert back to Celsius.

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