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What is the pressure in a 20.0 L cylinder filled with 45.4 g of oxygen gas at a temperature of 315 K?

A) 8.21 atm
B) 6.37 atm
C) 4.93 atm
D) 3.80 atm

1 Answer

1 vote

Final answer:

Using the Ideal Gas Law, the pressure in a 20.0 L cylinder filled with 45.4 g of oxygen gas at a temperature of 315 K is found to be 3.80 atm, which corresponds to option D.

Step-by-step explanation:

To determine the pressure in a 20.0 L cylinder filled with 45.4 g of oxygen gas at a given temperature, you can use the Ideal Gas Law, PV = nRT. The first step is to find the number of moles (n) of oxygen. One mole of O₂ weighs 32.00 g, so the number of moles of oxygen is:

n = 45.4 g O₂ / 32.00 g/mol = 1.41875 mol O₂

Next, apply the Ideal Gas Law using R, the universal gas constant, as 0.0821 L·atm·K⁻¹·mol⁻¹. We integrate the given temperature of 315 K and volume of 20.0 L to find the pressure (P):

P = nRT/V

P = (1.41875 mol) × (0.0821 L·atm·K⁻¹·mol⁻¹) × (315 K) / (20.0 L)

P = 1.84825 atm·K·L/mol·K / 20.0 L

P = 3.80 atm

Therefore, the pressure in the cylinder is 3.80 atm, which corresponds to option D.

User Orluke
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