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What is the true solution to the logarithmic equation below? 1094 [log(2x)] = 1

a. x - 2
b. y = 8
c. x - 64
d. x = 128

User Sanusi
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1 Answer

7 votes

Final answer:

To solve the equation 1094 [log(2x)] = 1, we isolate log(2x), convert it back to exponential form, and solve for x. The value of x should be approximately 1/2, but the given options do not match this solution, indicating a possible error in the question.

Step-by-step explanation:

To find the true solution to the logarithmic equation 1094 [log(2x)] = 1, we need to solve for x. First, divide both sides by 1094 to isolate the logarithm:

log(2x) = 1/1094

Next, we use the property that the logarithm of a product of two numbers is the sum of the logarithms of the two numbers, but since there is only one logarithm of a single product here, we'll move to the inverse operation to remove the logarithm:

10^(log(2x)) = 10^(1/1094)

Using the fact that the base-10 logarithm and the base-10 exponentiation are inverse operations, we have 2x = 10^(1/1094). Now calculate the value of 10^(1/1094) using a calculator.

Assuming the value is approximately 1 (since 1/1094 is a very small number), we get:

2x ≈ 1

Divide both sides by 2:

x ≈ 1/2

However, none of the options a-d given in the question correctly matches this solution. It is possible that there is a typo in the given options or the original equation. To address this question accurately, it would be necessary to revisit the initial problem to ensure that it is presented correctly.

User MattSull
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