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What is the equation of a line passing through the point (5, -3) and parallel to the line whose equation is 4y - x = 8?

a) y = 4x - 23
b) y = -4x + 23
c) y = 4x + 5
d) y = -4x - 5

User Micho Rizo
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1 Answer

1 vote

Final Answer:

The equation of the line passing through the point (5, -3) and parallel to the line 4y - x = 8 is y = 4x - 23. Option A is answer.

Step-by-step explanation:

Identify the slope of the parallel line:

The line 4y - x = 8 can be rearranged to slope-intercept form:

y = (1/4)x + 2

Therefore, the parallel line will have the same slope of 1/4.

Substitute the point (5, -3) into the point-slope equation:

The point-slope equation for a line with slope m passing through the point (x1, y1) is:

y - y1 = m(x - x1)

Substituting the values, we get:

y - (-3) = (1/4)(x - 5)

Solve for y:

y + 3 = (1/4)x - 5/4

y = (1/4)x - 23/4

Therefore, the equation of the parallel line is y = (1/4)x - 23/4, or simplified, y = 4x - 23.

Option A is answer.

User MethodManX
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