Final answer:
The expanded form of log(21x^2) is 2logx - log21, which is option b.
Step-by-step explanation:
The expanded form of log(21x^2) is 2logx - log21, which is option b. In logarithms, the rule states that the logarithm of a product is equal to the sum of the logarithms of its factors. So, log(21x^2) can be expanded as log(21) + log(x^2). Since log(x^2) is equal to 2log(x), the final expanded form is 2log(x) - log(21).