Question

What impulse must be imparted to a golf ball of mass 0.100 kg to give it a velocity of 74.0 m/s? If the golf club is in contact with the ball as it is accelerated over an interval of 1.50 cm, estimate the average force exerted on the ball by the club.

A) 0.0074 N
B) 0.74 N
C) 7.4 N
D) 74 N

Answer 1

The impulse imparted to the golf ball is 7.4 kg·m/s and the average force exerted on the ball by the club is approximately 36.6 kN.

Step-by-step explanation:

To find the impulse needed to give a golf ball a velocity of 74.0 m/s, we can use the equation:

Impulse = mass x change in velocity

Impulse = 0.100 kg x 74.0 m/s = 7.4 kg·m/s

The average force exerted on the ball can be estimated by dividing the impulse by the contact time. Given that the ball is accelerated over an interval of 1.50 cm, which is 0.015 m, the contact time can be estimated as:

Contact time = distance/velocity = 0.015 m/74.0 m/s = 0.000202 s

Average force = Impulse/contact time = 7.4 kg·m/s/0.000202 s = 36633.7 N = 36.6 kN

Therefore, the average force exerted on the ball by the club is approximately 36.6 kN.