Question

Zinc reacts with hcl to form h2 gas. if you want to make 0.234 moles of h2 gas and have excess zinc, how many milliliters of 3.2 m hcl do you need for the reaction?

Answer 1

To produce 0.234 moles of H2 gas, you would need 8.53 grams of 3.2 M HCl solution, which is equivalent to approximately 8.53 milliliters of the solution.

Step-by-step explanation:

To find the number of milliliters of 3.2 M HCl needed to produce 0.234 moles of H2 gas, we need to use the balanced chemical equation and stoichiometry. From the balanced equation: Zn + 2HCl -> ZnCl2 + H2, we know that 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of H2 gas.

So, we can set up a ratio:

(0.234 moles H2)/(1 mole H2) = (x moles HCl)/(3.2 M HCl)

Solving for x, we find that x = 0.234 moles HCl.

Since 1 mole of HCl is equivalent to 36.46 grams, the mass of 0.234 moles of HCl is (0.234 moles HCl)(36.46 g/mole) = 8.53 grams HCl. Knowing that the molar mass of HCl is 36.46 g/mole, we can convert grams to milliliters using the density of the solution.