Final answer:
The solubility product (Ksp) of CdS can be calculated by determining the concentrations of the Cd²+ and S²- ions in the saturated solution of CdS. The water solubility of CdS is given as 0.13 g/L, which can be converted to moles per liter. Since CdS dissociates into Cd²+ and S²- ions in a 1:1 ratio, the concentration of both ions will be the same in the saturated solution. The Ksp is then calculated using the formula [Cd²+][S²-]. The Ksp of CdS is found to be 8.1 x 10^-7.
Step-by-step explanation:
The solubility product (Ksp) is a measure of the extent to which a compound dissolves in water. It represents the equilibrium constant for the dissolution of a solid compound into its constituent ions in a solution. To calculate the Ksp of CdS, we first need to determine the concentrations of the Cd2+ and S2- ions in the saturated solution of CdS. The water solubility of CdS is given as 0.13 g/L. To convert this to moles per liter, we need to divide by the molar mass of CdS (144.47 g/mol).
0.13 g/L ÷ 144.47 g/mol = 0.0009 mol/L
Since CdS dissociates into Cd2+ and S2- ions in a 1:1 ratio, the concentration of both ions will be the same. Therefore, the concentration of Cd2+ and S2- ions in the saturated solution of CdS is 0.0009 mol/L.
Now, we can calculate the Ksp using the formula:
Ksp = [Cd2+][S2-]
Ksp = (0.0009 mol/L)(0.0009 mol/L)
Ksp = 8.1 x 10-7