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The angle θ₁ is located in quadrant iv , and sinθ₁=-10/13 . what is the value of [cos(θ₁)]?

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Final answer:

The value of cos(θ1) is -sqrt(69/169)

Step-by-step explanation:

To find the value of cos(θ1), we can use the trigonometric identity sin^2(θ1) + cos^2(θ1) = 1. Since we already know that sin(θ1) = -10/13, we can substitute this value into the equation:

sin^2(θ1) + cos^2(θ1) = 1

(-10/13)^2 + cos^2(θ1) = 1

Simplifying the equation:

100/169 + cos^2(θ1) = 1

cos^2(θ1) = 69/169

Taking the square root of both sides:

cos(θ1) = ±sqrt(69/169)

Since θ1 is located in quadrant IV and sin(θ1) is negative, cos(θ1) must also be negative. Therefore, the value of cos(θ1) is -sqrt(69/169).

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