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Suppose that on a particular day, the atmospheric pressure supports a column of water to a height of 2.70 m. calculate the corresponding atmospheric pressure in pascals.

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Final answer:

The corresponding atmospheric pressure in pascals that supports a column of water to a height of 2.70 m is approximately 26,487 Pa, calculated using the hydrostatic pressure formula with a water density of 1,000 kg/m³ and acceleration due to gravity of 9.81 m/s².

Step-by-step explanation:

To calculate the corresponding atmospheric pressure in pascals (Pa) when a column of water is supported to a height of 2.70 m, we use the formula for hydrostatic pressure, p = hρg, where h is the height of the water column, ρ is the density of water, and g is the acceleration due to gravity. Assuming that the density of water is approximately 1,000 kg/m³ (or 1 g/cm³) at 25 °C, and the acceleration due to gravity is 9.81 m/s², the calculation would be as follows:

p = hρg = 2.70 m × 1,000 kg/m³ × 9.81 m/s²

Therefore, the atmospheric pressure supporting the 2.70 m high water column is:

p = 2.70 m × 1,000 kg/m³ × 9.81 m/s² = 26,487 Pa

This means that the atmospheric pressure is approximately 26,487 pascals.

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