Final answer:
The volume of a balloon heated from 24.0 °C to 48 °C increases from 1.20 liters to approximately 1.30 liters according to Charles's Law.
Step-by-step explanation:
The question involves calculating the change in volume of a balloon when it is heated, using concepts from thermodynamics, specifically Charles's Law. This law states that if the pressure remains constant, the volume of a gas is directly proportional to its temperature measured in Kelvin. To find the new volume after heating the balloon from 24.0 °C (297.15 K) to 48 °C (321.15 K), we use the formula:
V1/T1 = V2/T2
Where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature. Plugging in the values we have:
(1.20 L / 297.15 K) = (V2 / 321.15 K)
Now we solve for V2:
V2 = (1.20 L × 321.15 K) / 297.15 K
V2 = 1.30 liters
Therefore, the new volume of the balloon when heated to 48 °C is 1.30 liters.