Final answer:
The maximum height reached by a ball thrown vertically with an initial velocity of 60 m/s is calculated using the kinematic equation, resulting in a height of 183.49 meters.
Step-by-step explanation:
To calculate the maximum height reached by a ball thrown up vertically with a velocity of 60 m/s, we can use the kinematic equation that relates initial velocity, acceleration due to gravity, and maximum height (h):
h = v² / (2g)
where v is the initial velocity, and g is the acceleration due to gravity (approximately 9.81 m/s² on Earth's surface). Since the ball is thrown straight up, we only consider the vertical motion.
Plugging the values into the equation, we get:
h = (60 m/s)² / (2 * 9.81 m/s²) = 3600 m²/s² / 19.62 m/s² = 183.49 m
Therefore, the maximum height reached by the ball is 183.49 meters.