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A 95.0 db sound wave comes through an open window of area 0.800 m2. how much acoustic energy passes through the window in a 17.0 min interval?

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Final answer:

The acoustic energy passing through the window is approximately 2414.4 joules in a 17.0 minute interval.

Step-by-step explanation:

To calculate the acoustic energy passing through the window, we need to determine the sound intensity level and use it to find the energy. The formula to calculate sound energy is:

Energy = Intensity * Area * Time

Given that the sound wave has a decibel (dB) level of 95.0 dB, we can convert it to intensity using the formula: Intensity = 10^((dB - 12)/10). Therefore, the intensity of the sound wave is approximately 0.316 watts/m².

Using the given area of the window as 0.800 m² and the time interval as 17.0 minutes (which needs to be converted to seconds), we can plug these values into the energy formula to find:

Energy = 0.316 * 0.800 * (17.0 * 60)

Calculating this, the acoustic energy passing through the window in a 17.0 minute interval is approximately 2414.4 joules.

User Karl Johan Vallner
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