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An object starting from rest travels 720 meters in three seconds. calculate acceleration

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Final answer:

The acceleration of an object that starts from rest and travels 720 meters in 3 seconds is calculated using the kinematic equation for uniformly accelerated motion. By substituting the values into the equation, we find that the acceleration is 160 m/s².

Step-by-step explanation:

To calculate the acceleration of an object that starts from rest and travels a certain distance in a given time, you can use the kinematic equation for uniformly accelerated motion, which is:

s = ut + ½at²

Where 's' is the displacement, 'u' is the initial velocity, 't' is the time, and 'a' is the acceleration. For an object starting from rest (u=0) and traveling 720 meters in 3 seconds, we have:

  • s = 720 m
  • u = 0 m/s (since it starts from rest)
  • t = 3 s

By substituting the given values into the equation, we have:

720 = 0 × 3 + ½a × (3²)

720 = ½a × 9

720 = 4.5a

a = 720 / 4.5

a = 160 m/s²

Therefore, the required acceleration is 160 m/s².

User TLGreg
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