Question

An aqueous antifreeze solution is 40.0% ethylene glycol (c2h6o2) by mass. the density of the solution is 1.05g/cm3. what is the molarity (m), molality (m) and mole fraction of the ethylene glycol?

Answer 1

The solution involves converting the mass percentage and density of the ethylene glycol solution to find molarity, molality, and mole fraction. This is done by calculating the moles of ethylene glycol and the volume or mass of the solution as required.

Step-by-step explanation:

To calculate the molarity, molality, and mole fraction of ethylene glycol in the aqueous solution, we follow these steps:

First, we find the mass of ethylene glycol using its given percentage by mass and the density of the solution.

Then, we calculate the moles of ethylene glycol using its molar mass (62.07 g/mol).

For molarity, we need to find the volume of solution using its density and then divide the moles of ethylene glycol by this volume in liters.

To find molality, we need to calculate the mass of water in the solution and then divide the moles of ethylene glycol by the mass of water in kilograms.

For mole fraction, we need to find the moles of water present in the solution and then divide the moles of ethylene glycol by the total moles of both components.

Keywords such as mass percentage, density, molar mass and mole fraction are essential in solving this problem.