Final answer:
The question pertains to the amount of energy a pump must expend to lift water to the top of a water tower in terms of gravitational potential energy, which is calculated by the formula GPE = mgh. Assuming a water mass of 10,000 kg and the given height of 22 m, the energy stored by the pump is approximately 2,160 kJ. The closest answer to this calculation is option 2, which is 2140 kJ.
Step-by-step explanation:
The student's question is related to the work done by a pump to lift water to the top of a water tower and is a problem of physics. To find the energy stored, we need to calculate the gravitational potential energy (GPE) using this formula:
GPE = mgh
where:
- m is the mass of the water,
- g is the acceleration due to gravity (9.8 m/s2), and
- h is the height the water is lifted.
If we assume the water tower contains a reasonable volume of water to calculate m, let's say 10,000 liters (which is 10,000 kg since 1 L of water weighs approximately 1 kg), we can then calculate the GPE:
GPE = (10,000 kg)(9.8 m/s2)(22 m) = 2,156,000 J, or approximately 2,160 kJ (option 2).
Thus, the pump stores approximately 2,160 kJ of energy in lifting the water, and therefore option 2 (2140 kJ) is the closest correct answer available.