Final answer:
The rate of change of the height of the cone is approximately 0.067 meters per second.
Step-by-step explanation:
To find the rate of change of the height, we need to use the formula for the volume of a cone and differentiate it with respect to time.
The formula for the volume of a cone is: V = (1/3)πr²h, where V is the volume, r is the radius, and h is the height.
We are given that the radius is increasing at a rate of 4 meters per second (dr/dt = 4 m/s) and the volume is increasing at a rate of 904 cubic meters per second (dV/dt = 904 m³/s).
At the instant when the radius is 1010 meters and the volume is 489 cubic meters, we can substitute these values into the volume formula.
Solving for the rate of change of the height (dh/dt), we can differentiate the volume formula with respect to time and solve for dh/dt.
dh/dt = (3dV/dt) / (4πr²)
Substituting the given values, we have:
dh/dt = (3 * 904) / (4 * π * (1010)²)
dh/dt ≈ 0.067 meters per second