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From the theory section of this handout, the ideal gas law is pv=nrt. rearranged, the equation can be written as p=(nr/v)t. if pressure is on the y-axis of your plot, and temperature is on the x-axis of your plot, what is the slope?

User Dumitru
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Final answer:

For the calibrated ideal gas law equation p=(nr/v)t, when graphed with pressure on the y-axis and temperature on the x-axis, the slope is (nr/v), which is the rate at which pressure changes with respect to temperature for a given amount of gas in a fixed volume.

Step-by-step explanation:

If we consider the rearranged ideal gas law equation p=(nr/v)t, where p represents the pressure of the gas, t the kelvin temperature, n is the number of moles of the gas, v is the volume of the gas, and r is the ideal (universal) gas constant, and we plot pressure on the y-axis and temperature on the x-axis, the slope of the plot represents the change in pressure with respect to temperature (Δp/ΔT). In this equation, the product nr/v is constant for a given amount of gas and volume, thus if we consider n, r, and v to be constants for a particular gas under controlled conditions, the slope of the pressure-temperature plot would be (nr/v), representing the rate at which pressure changes with temperature.

User Hyperdrive
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