Final answer:
In a cross between a homozygous dominant turkey and a heterozygous turkey for the 'gobble gobble' trait, half of the offspring will be heterozygous and half will be homozygous dominant as no gg genotype is possible.
Step-by-step explanation:
When a homozygous dominant turkey for the 'gobble gobble' trait is crossed with a heterozygous turkey, we can predict the offspring's genotypes using a Punnett square. Since 'gobble gobble' is dominant over 'gobble,' let's denote the dominant allele as 'G' and the recessive allele as 'g'.
The homozygous dominant turkey's genotype is GG, and it can only contribute the G allele. The heterozygous turkey's genotype is Gg, and it can contribute either a G or a g allele. There are two possible allele combinations for the offspring from this cross - GG or Gg - but no gg offspring because neither parent can contribute two recessive alleles.
Assuming random mating, the offspring will be either homozygous dominant (GG) or heterozygous (Gg). No homozygous recessive offspring (gg) will be produced since a homozygous dominant individual cannot carry the recessive gene. Therefore the correct answer is: c) Half heterozygous and half homozygous dominant offspring.