Question

The number of seconds, t it takes for an object to fall a distance of d feet can be found using the formula t=2dg‾‾‾√, where g is the constant acceleration due to gravity, 32ftsec2. how many feet does an object fall in 2 seconds?

a) 32 feet
b) 64 feet
c) 96 feet
d) 128 feet

Answer 1

An object falls 64 feet in 2 seconds when dropped from rest under the influence of Earth's gravity, given the acceleration due to gravity is 32 feet per second squared.

Step-by-step explanation:

To determine how far an object falls in 2 seconds under the influence of Earth's gravity, you can use the formula t = √(2d/g), where t is time in seconds, d is distance in feet, and g is the acceleration due to gravity, which is 32 feet per second squared. We can rearrange this formula to solve for distance (d) as d = g · t2 / 2.

Substitute the known values to find the distance fallen in 2 seconds:
d = 32 ft/sec2 · (2 sec)2 / 2
d = 32 · 4 / 2
d = 128 / 2
d = 64 feet.

Therefore, the correct answer is (b) 64 feet.