Final answer:
The volume of a 0.175 M Al(NO3)3 solution containing 0.0591 moles is found by dividing the moles of solute by the molarity of the solution.
Step-by-step explanation:
To determine the volume of a 0.175 M Al(NO3)3 solution that contains 0.0591 moles of Al(NO3)3, you can use the formula:
Molarity (M) = Moles of solute / Volume of solution in liters (L)
Rearrange this formula to solve for the volume:
Volume of solution in liters (L) = Moles of solute / Molarity (M)
Insert the provided values:
Volume in liters = 0.0591 moles / 0.175 M
This calculation gives you the volume of the solution in liters.