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Determine the force on a 3.0C charge placed 5m from the midpoint of a moment 4cm and separation 0.2m on a line perpendicular to the dipole.

User Veepsk
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1 Answer

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Final answer:

To determine the force on a charge placed 5m from the midpoint of a dipole, you can use Coulomb's law and the formula F = k * ((q+ * q-)/(0.2m^2)).

Step-by-step explanation:

The force on a charge placed 5m from the midpoint of a dipole can be determined using Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

For this problem, we can calculate the force using the formula:

F = k * (q1 * q2) / r^2

Where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

In this case, we have a charge of 3.0C placed 5m away from the midpoint of a dipole with a moment of 4cm and a separation of 0.2m.

Since the charge is placed on a line perpendicular to the dipole, we can consider the dipole as two point charges separated by the distance of the dipole. Let's assume the charges are q+ and q-.

The force on the charge can then be calculated as:

F = k * ((q+ * q-)/(0.2m^2))

Given the information provided, we can substitute the values into the formula:

F = k * ((4cm * 0.2cm)/(0.2m^2))

Now we can calculate the force using the given value of k and perform the necessary unit conversions to get the final answer.

User JackSun
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