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Construct the expression kp for the following reaction 2sn(s) 4cl2 (g) > 2sncl4(l)

User Binary
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Final answer:

For the reaction 2Sn(s) + 4Cl2(g) → 2SnCl4(l), a Kp expression is not applicable in its typical form since the product is a liquid. The general relationship between Ke and Kp is Kp = Ke(RT)^Delta n, which involves gaseous reactants and products only.

Step-by-step explanation:

To construct the expression Kp for the reaction 2Sn(s) + 4Cl2(g) → 2SnCl4(l), we need to consider the phases of the reactants and products. However, under the stated conditions, Kp only pertains to gaseous substances. In this reaction, both reactants and products are not all gases since tin tetrachloride (SnCl4) is in the liquid state. Therefore, for a liquid product, the Kp expression only includes the gaseous reactants. According to the ideal gas law, the equilibrium expression for this reaction in terms of partial pressures is not applicable here as the product is not a gas. If the product were a gas, the expression for Kp would be (PProduct)c/(PReactant1)a(PReactant2)b, but this cannot be constructed directly in this case due to the liquid product.

Focusing on general practice, the relation between Ke and Kp is given by the formula Kp = Ke(RT)^Δn, where R is the ideal gas constant, T is the temperature in Kelvin, and Δn is the change in moles of gas. For the reaction given, no calculation is necessary for Kp because of the liquid product.

User ContentiousMaximus
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