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Balance the following reaction in KOH. What are the coefficients in front of C5H12O2 and KMnO4 in the balanced reaction?

C5H12O2(aq) + KMnO4(aq) → C5H6O4K2(aq) + MnO2(aq)

1 Answer

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Final answer:

To balance the chemical equation C5H12O2(aq) + KMnO4(aq) → C5H6O4K2(aq) + MnO2(aq), the coefficients in front of C5H12O2 and KMnO4 in the balanced reaction are 3 and 14 respectively.

Step-by-step explanation:

To balance the chemical equation C5H12O2(aq) + KMnO4(aq) → C5H6O4K2(aq) + MnO2(aq), we need to ensure that the number of each type of atom is the same on both sides of the equation.

In this case, the balanced equation is:

3C5H12O2(aq) + 14KMnO4(aq) → 5C5H6O4K2(aq) + 7MnO2(aq) + 4KOH(aq).

The coefficients in front of C5H12O2 and KMnO4 in the balanced reaction are 3 and 14 respectively.

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